Hi, i am new to these forums.
i need help on a calorimetry problem:
CuSO4 -> Cu^2+ + SO4^-2
0.800 g of CuSO4 is dropped into a calorimeter with 43.0 g of water at an initial temperature of 18.3 degree C. As CuSO4 dissolves in water, the temperature rose to 20.2 degree C. What value is the heat enthalpy obtained from the data?
i know the answer is -68.2 kJ but i don't know how to get there.
this is as far as i got:
(43.0)(4.184)(20.2-18.3) = 341 J
please help and show step by step explanations please.
thanks