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Enthalpy of Formation!!!
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Topic: Enthalpy of Formation!!! (Read 8989 times)
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lilns8252
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Enthalpy of Formation!!!
«
on:
March 20, 2009, 04:33:02 PM »
I have a couple homework questions due tonight and i've tried everything but i dont seem to understand!!!
the question is:
Using enthalpies of formation, calculate the quantity of heat produced when 4.65 of butane is completely combusted in air under standard conditions. The answer should be in kJ
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typhoon2028
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Re: Enthalpy of Formation!!!
«
Reply #1 on:
March 20, 2009, 04:46:41 PM »
4.65 what? Units? (grams, kilograms, pounds, moles)
After you know that, calculate the heat of formation of butane. This should be in kJ/mole.
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ARGOS++
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Re: Enthalpy of Formation!!!
«
Reply #2 on:
March 20, 2009, 04:47:33 PM »
Dear
nimritsohal
;
This page should be of help to you:
http://en.wikipedia.org/wiki/Standard_enthalpy_change_of_formation
And please use units!:
What is 4.65 meaning grams, or kg, or moles?
Good Luck!
ARGOS
++
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lilns8252
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Re: Enthalpy of Formation!!!
«
Reply #3 on:
March 20, 2009, 04:58:47 PM »
sorry i forgotto add the units.. it was 4.65 grams
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lilns8252
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Re: Enthalpy of Formation!!!
«
Reply #4 on:
March 20, 2009, 05:03:29 PM »
I solved for heat of formation of butane and got -5271kJ/mol... what do i do after that?? or is that the answer? because the units they want the answer in is just kJ.. wat happends to the moles then?
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ARGOS++
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Re: Enthalpy of Formation!!!
«
Reply #5 on:
March 20, 2009, 05:53:45 PM »
Dear
nimritsohal
;
If I’m correct, then Wiki reports another value than you:
http://en.wikipedia.org/wiki/Butane_(data_page
)
What's also required is a balanced reaction equation!
Good Luck!
ARGOS
++
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Enthalpy of Formation!!!