[posix_memalign]

How can I calculate the amount of carbon monoxide that occupies a volume of 140 dm^3 under normal conditions?

I tried using PV = nRT, but this didn't lead me to anything useful. What formula and approach should I use, and why?

Any help would be appreciated, thanks. :-)

[nj_bartel]

Check that you converted dm³ correctly, and that you used the correct R value (check your units).

[posix_memalign]

Check that you converted dm³ correctly, and that you used the correct R value (check your units).

But I don't understand how PV = nRT even is the correct procedure for this -- what should I solve the equation for?

[macman104]

It wants amount of CO, so is there a variable in there that can provide you with "amount" (that could be moles)?

[Arkcon]

Lets start by seeing what you've done.  Copy the forumula, they copy where you've plugged in values for the known variables.

[posix_memalign]

Lets start by seeing what you've done.  Copy the forumula, they copy where you've plugged in values for the known variables.

At first I have, PV = nRT,
P = 1 atm
V = 140 dm^3
R = 8.314 JK^(-1) mol^(-1)
T = 22 (degrees C)
n = molar mass

Then I get:

1*140 = n * 8.314*22
I solve for n and get ~0.755, which with 1 mol is ~755 grams?

[ARGOS++]

Dear posix_memalign;

There are several mistakes in your interpretation of the Ideal Gas Law:
               http://en.wikipedia.org/wiki/Ideal_gas_law  
(Wrong are your T, and n, and R!)

Do you know another equivalent unit for dm³?:
               http://en.wikipedia.org/wiki/Dm3 

So your result will not be correct in anyway.
Good Luck!
                    ARGOS⁺⁺

[posix_memalign]

Dear posix_memalign;

There are several mistakes in your interpretation of the Ideal Gas Law:
               http://en.wikipedia.org/wiki/Ideal_gas_law  
(Wrong are your T, and n, and R!)

Do you know another equivalent unit for dm³?:
               http://en.wikipedia.org/wiki/Dm3 

So your result will not be correct in anyway.
Good Luck!
                    ARGOS⁺⁺

My revised solution is:

n = 140 / (0.08206 * 298)
n ~ 5.73

Which gives me 160 gram from the product: 5.73 * 28, where 28 is C + O (16+12).

Is 160 gram correct?

[ARGOS++]

Dear posix_memalign;

If you define normal condition as 1 atm and 25°C, then you are correct!

Usually normal conditions refer to STP, and that’s 1 atm and 0°C.
(For "STP Conditions" see Wiki.)

Good Luck!
                    ARGOS⁺⁺