This is a real, in-the-field question. Calcium polysulfate (CPS) reduces Cr(VI) to Cr(III) in groundwater.
If I have an assumed flow of 30 gallons per minute of groundwater that has an assumed steady Cr(VI) concentration of 1149 micrograms/liter, how much CPS (in volume per minute) do I need to add to treat the groundwater if 39 milliliters of CPS is needed to treat 1 gram of Cr(VI))?
I came up with 5.12 ml/min, but it just doesn't look right.
Thanks for taking a look!