If a sample of an ideal gas has it's volume doubled while its temperature remains constant, and the original pressure was 100 Torr, what is the new pressure in Torr?
Boyle's law states that the Pressure of a gas is inversely proportional to the Pressure of a gas at a constant temperature; V ~ 1/P
Thus, if the volume is doubled when the pressure is 100 Torr; V ~ 1/100 Torr
Then, when the volume is doubled, then the pressure in the previously stated Boyle's law doubles, and thus:
V ~ 1/200 Torr = 0.005 Torr, or, 2V ~ 1/100 Torr = V ~ (1/100 Torr) / 2 = 0.005 Torr.
Please correct me if I'm wrong.