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gravimetric determination of sulfate
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Topic: gravimetric determination of sulfate (Read 8360 times)
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bamster
Regular Member
Posts: 32
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gravimetric determination of sulfate
«
on:
May 20, 2009, 04:55:15 PM »
weight of BaSO4 product is 0.1597g
find mass of SO3 in sample
i got around 0.0549 g but i don't know for sure how to do it.
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ARGOS++
Sr. Member
Posts: 1489
Mole Snacks: +199/-56
Gender:
Re: gravimetric determination of sulfate
«
Reply #1 on:
May 20, 2009, 05:13:22 PM »
Dear
bamster
;
It seems you did it correct!
(I got 0.05475g SO
3
.)
If you would like to have your method checked, then please show us your work.
Good Luck!
ARGOS
++
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bamster
Regular Member
Posts: 32
Mole Snacks: +0/-11
Re: gravimetric determination of sulfate
«
Reply #2 on:
May 20, 2009, 05:19:04 PM »
i did
0.1597 x
80.0642 g/mol SO3
233.3906 g/mol BaSO4
= 0.0548 g
the thing i wasnt sure about is that in my book it has a ratio or something of 1 over 1 between known mass of BaSO4 and the molar mass calculation. I know it has something do if there were more SO's or something.
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ARGOS++
Sr. Member
Posts: 1489
Mole Snacks: +199/-56
Gender:
Re: gravimetric determination of sulfate
«
Reply #3 on:
May 20, 2009, 05:26:20 PM »
Dear
bamster
;
Your calculation is correct
, because there is only one SO
3
per BaSO
4
, so the stoichiometry tells you that the molar ratio is
1:1
.
Best will be, if you can do a few other examples!
Good Luck!
ARGOS
++
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gravimetric determination of sulfate