[Gweedo8]

A sample of CuSO4*5H2O was heated to 110 degrees C, where it lost water and gave another hydrate of copper (II) ion that contains 32.50% Cu.  A 98.77-mg sample of this new hydrate gave 116.66 mg or barium sulfate precipitate when treated with barium nitrate solution. What is the formula of the new hydrate?

The answer was given Copper Sulfate Dehydrate (CuSO4*2H2O) but how do I find this answer from this equation, it is extremely overwhelming and I have been reading my text for 3 hours now to find directions toward this solution with no help. Can someone please help???

[sjb]

How many moles of barium sulfate precipitated? How many moles of copper sulfate hydrate reacted? If 98.77 mg is that many moles, what is the molecular weight..?