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Topic: Hydrolysis question (salts in water)  (Read 2765 times)

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Offline maccha

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Hydrolysis question (salts in water)
« on: June 19, 2009, 11:43:55 PM »
Take for example the hydrolysis of NaF.

Na doesn't react with water but F does according to the equilibrium equation:

H20 + F- <---> HF + OH-

So a basic solution is said to be formed. What I don't understand is that, isn't HF a stronger acid than F- is a base? Wouldn't the solution therefore end up being acidic?

Offline UG

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Re: Hydrolysis question (salts in water)
« Reply #1 on: June 20, 2009, 12:59:34 AM »
HF is actually quite a weak acid in the scheme of things (if you want to know why  http://www.chemguide.co.uk/inorganic/group7/acidityhx.html), the OH- is the basic part which makes the solution basic.

Offline Borek

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Re: Hydrolysis question (salts in water)
« Reply #2 on: June 20, 2009, 03:49:31 AM »
Strengths of both acid and conugate base are related.

http://www.chembuddy.com/?left=pH-calculation&right=bronsted-lowry-theory

This is a delicate equilibrium, that requires presence of both HF and F-. If you start with HF only, it will dissociate producing H+ and F- and you will end with acidic solution. If you start with F- only it will react with water producing OH- and HF and you will end with basic solution. Pay special attention to this only part of above statements.
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