25.0 ml of a solution containing both
and
is titrated with 23.0 ml of a 0.0200 M
in dilute sulfuric acid. As a result, all of the
ions are oxidized to
ions.
Next, the solution is treated with Zn metal to convert all the
to
ions. Finally, the solution containing only the
ions requires 40.0 ml of the same
solution for oxidation to
.
Given that the net ionic equation is
, calculate the molar concentrations of the
and
ions in the original solution.