"Naturally occuring boron is composed of only two isotopes 10|5 B and 11|5 B with atomic masses of 10.0129 and 11.00931 respectively. To account for the atomic mass of 10.811, what must be the percentage abundance of each isotope?"
With my working I'm saying x10.0129 + y11.00931 = 10.811 where x and y are the decimals expressing % e.g. 76% = x = 0.76.
Now that has 2 unknowns and I can't solve it.
This is probably extremely basic and I must have missed the lecture. Can anybody tell me how to solve this?
The answer is 19.902% 10|5 B