[akxt]

What is standard delta g at 500k for the following reaction?
Cu(s)+H2O(g)-->CuO(s)+H2(g)
I'm given the standard delta H and standard delta S at 298K. I calculated delta S and H to be
-48.7 and 84.5, respectively. I plugged into Delta G = Delta H - T(DeltaS).

Did I do this correctly? (Sorry, didn't want to type out the table of data given delta h and s)


-What is the change in entropy of 4.40mL of liquid benzene (C6H6, d = .879g/mL) is combusted in the presence of 37.3L of O2 gas, measured at 298K and 1atm pressure?(R=.0821L*atm/(K*mol)]
2C6H6(l)+15O2(g)-->12CO2(g)+6H2O(l); delta S = -437.7J/K at 298K.

Am I supposed to use the standard delta G = -RT(lnK) formula? I don't understand where I'm suppose to go from here to get the new delta S.

Thanks for any help