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Topic: Moles to dissolve AgBr in water?  (Read 4894 times)

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Offline nernst

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Moles to dissolve AgBr in water?
« on: July 28, 2009, 09:21:49 PM »
Here is the question I'm working on:

How many moles of Na2S2O3 must be added to dissolve .030 mol AgBr in 1.0 L of water?

Kf = 2E13
Ksp= 3.3E-13

balanced equation :

AgBr + 2S2O32- <-----> Ag(S2O3)3- + Br-

I                                          0                     0
C                  ?                     +.030                +.030
E
         .01168                .030                   .030

Now, I set up an I.C.E table for it. This is how far I get, and then I'm rather confused about how to proceed?



Offline plankk

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Re: Moles to dissolve AgBr in water?
« Reply #1 on: July 29, 2009, 02:14:44 AM »
You are really close to correct answer.  ;)

Let's think. As your ICE table "says" in equilibrium should be .01168 mol per litr of S2O32-. Also in that state should be .030 mol per litr of [Ag(S2O3)]3-. How many moles of S2O32- is needed to create .030 mol of [Ag(S2O3)]3- (remeber that in the task they ask for 1.0 L)? The sum of that value and that in equilibrium state is the whole demand for Na2S2O3.

Offline nernst

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Re: Moles to dissolve AgBr in water?
« Reply #2 on: July 30, 2009, 03:03:26 PM »
You are really close to correct answer.  ;)

Let's think. As your ICE table "says" in equilibrium should be .01168 mol per litr of S2O32-. Also in that state should be .030 mol per litr of [Ag(S2O3)]3-. How many moles of S2O32- is needed to create .030 mol of [Ag(S2O3)]3- (remeber that in the task they ask for 1.0 L)? The sum of that value and that in equilibrium state is the whole demand for Na2S2O3.

What I had trouble with was working backwards to calculate the moles.

Offline plankk

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Re: Moles to dissolve AgBr in water?
« Reply #3 on: July 30, 2009, 03:35:52 PM »
So let's try step by step...

Answer for that question: how many moles of S2O32- is needed to create ,030 mol of [Ag(S2O3)]3-?

Offline nernst

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Re: Moles to dissolve AgBr in water?
« Reply #4 on: July 30, 2009, 03:48:09 PM »
So let's try step by step...

Answer for that question: how many moles of S2O32- is needed to create ,030 mol of [Ag(S2O3)]3-?

2

Offline plankk

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Re: Moles to dissolve AgBr in water?
« Reply #5 on: July 31, 2009, 01:38:40 AM »
2 yes, but to create 1 mol of complex. We want to have .030 mol of complex so we need .060 mol of S2O32-.

In equilibirum state the concentartion of thiosulfate (as you count) is .01168 mol/l, so in 1 litr of water should be .01168 mol of S2O32-.

As you see the thiosulfate occures as a free anion and also as a linked in complex. You must calculate the whole demand for sodium thiosulfate, so the sum of moles from that two sources will be your answer.

BTW. In my post I found a mistake. Of course should be [Ag(S2O3)2]3- instead of [Ag(S2O3)]3-
« Last Edit: July 31, 2009, 01:49:23 AM by plankk »

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