You gave almost the right answer yourself:
Fe
2O
3 with dilute sulphuric acid gives a solution that contains Fe
3+ ions and sulphate ions, no trace of FeSO
4.
I would proceed as follows:
Add a reducing agent. Pure iron powder, in excess, is the most suitable, because no purification afterwards is necessary. You might also pass SO
2 through the solution. But I think the Fe is preferable.
After the reaction has gone to completion, the yellow colour of the solution should have turned pale green. Let the solution evaporate to get the solid FeSO
4.
Avoid the entrance of oxygen during the evaporating process (adding dry ice could be of help because it gives a protective carbon dioxide layer above the solution).
Equation without the sulphate spectator ions:
Fe(s) + 2 Fe
3+(aq)
3 Fe
2+(aq)