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Topic: Empirical/Molecular Formula from Combustion Equation  (Read 11319 times)

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Offline s3a

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Empirical/Molecular Formula from Combustion Equation
« on: September 08, 2009, 07:22:57 PM »
A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of compound yields 16.01 mg CO2 and 4.37 mg H2O. The molar mass of the compound is 176.1 g/mol.

a) What is the empirical formula of the compound? [Answer: C3H4O3]

b) What is its molecular formula? [Answer: C6H8O6]

Any help would be greatly appreciated!
Thanks in advance!
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Offline Moss

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Re: Empirical/Molecular Formula from Combustion Equation
« Reply #1 on: September 08, 2009, 08:11:54 PM »
Hey
Check out this. has steps and examples for you to follow.
http://faculty.ncc.edu/LinkClick.aspx?fileticket=xblMFql5cJ4%3D&tabid=1827

There's steps on how to find the empircal and molecular formula
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Offline Fridushka

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Re: Empirical/Molecular Formula from Combustion Equation
« Reply #2 on: September 09, 2009, 02:48:55 AM »
Write the balanced equation of the combustion reaction and show some work!
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