The carbon in question is only chiral if it has 4 nonidentical groups surrounding it. Directly attached to the carbon of interest in the this problem is a hydrogen, a methyl group, and two methylene groups. Since the methylene groups are the same you have to keep looking further and further out from the methylene groups on each side to find a mismatch at which point you can conclude that the carbon of interest is chiral. In this case, you never find a mismatch...so the carbon in question is not chiral. Since its not a chiral carbon even if you switch the 3D in the picture it doesn't matter, you are looking at the same molecule.