January 15, 2025, 07:11:11 PM
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Topic: Molecular orbitals in CO- why are energy levels (n=1,2...) shown for this?  (Read 6432 times)

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Offline Kalibasa

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I'm looking at an energy diagram of CO, and I understand the important point (how the contributions of the two atoms aren't equally distributed- the higher-energy carbon contributes more to the higher-energy, antibonding MO's).  I'm confused, though, about the numbers used before the pi's and sigma's. Here is the diagram:

4σ*
2π*


2σ*


I'm guessing the numbers beforehand correspond exactly to the basic energy levels we learned in intro chem (ex. n=1, n=2), and that here the energy levels are "out of order" (ex. 3 before 2) because the antibonding orbitals are that much higher in energy than bonding ones. But I don't understand why 1π is higher than 2σ*; if they both have one node, shouldn't the n=2 orbital be higher?

I also don't understand why these numbers are used here but weren't used before, for the homonuclear diatomic molecules. N2, for instance, has the exact same orbital progression as CO, but there we didn't list energy levels (it was just σ, σ*, etc). Why do we list them here?

Thanks!

Offline KritikalMass

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Hmm, this was a difficult question! I looked all over the net and in my old textbooks for about 2 hours and couldn't find a good answer. I am unable to help you out, but will post a couple of pics so that maybe someone can have a better idea of what you are referring to.

Offline jj74

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I'm not sure, but maybe it's a simple progressive number:
lower Sigma:1, the first sigma higher 2 and so on..
the same for the Pi orbitals; you could try asking in the chemical physics forum
It's a town full of losers, I'm pulling out of here to win

Offline cth

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You can have a look at this webpage http://courses.chem.psu.edu/chem210/mol-gallery/co/co.html for a nice explanation :)

Quote
4σ*
2π*


2σ*


To put it simply:
The 1π and 2π* orbitals are located more onto the oxygen atom, which is more electronegative than the carbon. These orbitals are lowered in energy.
The 3σ and 4σ* orbitals are more onto the carbon atom. So, it is a bit higher in energy.
Overall, the σ orbitals become higher in energy than the π.

Offline KritikalMass

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Hey thanks cth! I'm not the OP but glad someone came along to give an answer- that question was buggin' me like crazy!

Offline Kalibasa

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Thank you all :)

Offline soot

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They are merely markers to separate the sigma from pi.

ie if you are using symmetry to form MOs)

1a1 (sigma)
2a1 (sigma star)

They are sequential and not necessarily a reflection of the principal quantum number.

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