[Geddoe]

Citric acid, H3C6H5O7, reacts with potassium hydroxide to produce potassium citrate and water. How
many grams of citric acid are required for complete reaction with 20.0 mL of 0.200 M potassium hydroxide?
The molar mass of citric acid is 192.125 g/mol. (Hint: start by writing the balanced equation for the
reaction.)


Here is my work:

 H3C6H5O7 + 3 KOH => C6H5K3O7 + 3 H2O

M = n / v

n = M * v
= (0.200 M KOH * 20.0mL) * (1 L / 1000mL) = 0.004 mole KOH

0.004 mole KOH * (1 mole H3C6H5O7  / 3 mole KOH) * (192.125 g/mol / 1 mole H3C6H5O7) = 0.256166667g H3C6H5O7


Is this correct?

[cliverlong]

You have made the same mistake in your other, highly similar, post

moles is not equal to mol / mL * L / mL

Clive

[Geddoe]

How can I correct this mistake? In the other topic I believe I did it correctly... 

[Borek]

You are OK, Clive is wrong. I suppose he misread your post and missed fact that M is mol/L.

[cliverlong]

I made the same mistake as in my other post on the related question from Geddoe