I have serious issues with inductive effects and their effect on halogenation.
What will be the major product when a mole of HBr is reacted with one mole of penta(1,3)diene?
This is similar to my previous post.
Obviously, due to markovnikov's rule, if the double bond at 1 is broken, Br will be substituted at 2. But, if double bond at 3 is broken, will the postive charge come on 3, as it will be resonance stabilised?? And I also know I should consider 1,4 addition. Im just confused which double bond will be affected and why.
Please help me out. I hope you guys understand where im lacking info.