I think you should use mole ratios, because you have no other ways where to put lead, right? So there may be other compounds, but you can stick to the lead - containing.
Well, i did those calculations: since we have mole ratios 1/5...
aA + bB
sS
w[%]=a/s*M(A)/M(S)*m
S/m
sample*100
w[%]=1/5*1875,75/278,1*2,36/3,81*100
and i did the same: 83,5%. you sure that's wrong?