[ryan18]

Start with:
volume of hydrochloric acid (up to 150mL of 0.25M hydrochloric acid)
mass of sodium carbonate (solid, up to 2 grams.)

It gives me a very weird path of how to find the end result, which is the molarity of hydrochloric acid.

The path it gives me is this:

g Na₂CO₃ ----> x() ----> mol Na₂CO₃------> x() -------> mol HCl --------(THEN IT INTERJECTS WITH AN ARROW IN THE MIDDLE OF THIS ARROW SAYING "xx.xx mL HCL")---->x() ----->end with Molarity of hydrochloric acid.

If needed I can scan the picture in, but I am just not getting what to do here.
Any and all help is appreciated!
Thanks, Kyle!

[Mitch]

It is weird, but I imagine the first x is asking for the molar mass of Na₂CO₃, which would be...?

[ryan18]

I can do everything up to the mol HCl, I am stuck at that point. I have no clue what its asking for or how to get the molarity of the hydrochloric acid...

[ryan18]

I guess I left out some information...

The lab is entitled: "Reenactment of an 18th century analysis: Amount of Acid in Solution"

There is a balanced equation:

2HCl(aq) + Na₂CO₃(s) --> 2NaCl(aq) + CO₂(g) + H₂O(l)

Overview:
You and your partner are to design and test a procedure to determine how much solid sodium carbonate will react with a known(predetermined) volume of hydrochloric acid, then use the information to calculate an experimental value of the concentration (molarity) of HCl in the acid. The equation is the one listed above.

[Mitch]

If you were able to calculate mol HCl, then using the 0.25M stated earlier in the problem it should be possible to get xx.xx mL HCL. But I agree with you that this is a strange setup for a problem and providing a scan of this problem might be prudent.

[ryan18]

http://i16.photobucket.com/albums/b50/XxspearsjunkiexX/Scan001.jpg

Hopefully that link will explain it all haha, its the prelab.

[Mitch]

Looks like you can assume whatever you want for mL HCl.