Thanks for the reply. Ya, the 7ml was the average volume of the titrant.
Alright, so:
3.5x10-4 moles of I2 x 1 mole IO3/3 moles I2 = 1.17x10-4 moles of IO3
Dividing that by the volume of the aliquot, gives a concentration of: 4.67x10-3M
But since it was originally dissolved in a 250mL, we multiply by that to get the actual number of moles of IO3: 1.17x10-3 which is then multiplied by the MW (214) to give 0.2497g of KIO3 which in the end gives a 27.2% purity.
I know the calculated purity should be higher than that of the recrystallization (7.925%), but should there be such a discrepancy?