This is more of a general chemistry question. But this is from my physical chemistry class so I thought I'll put it here. So here's the question:
A=CH
3COCH
3I=CH
3COHCH
3+E=CH
3COHCH
2P=CH
3COCH
2Br
Using the following mechanism:
A + H
+
I. With equilibrium constant "K"
I + H
2O
E + H
3O
+. With k
1 going forward, and k
-1 going backwards.
E + Br
2 P + H+ + Br-. With k
2 going forward.
I'm suppose to prove this: d[P]/dt = k
1 k
2 K [A][H
+][Br
2] / k
-1[H
+] + k
2[Br
2].
I've tried solving this for a while and didn't quite get it. Here's what I did. Using the rate law, I know the formation of the product "P" is the rate constant times the reactant.
P=K
2 *[Br
2]*E
P=K
2 *[Br
2]*k
1 * I / k
-1 [H
+]
P=K
2 *[Br
2]*k
1 * K*A*H
+ / k
-1 [H
+]
Doubt I did this right. But that's as far as I can go. Not sure how to get the other part: k
2[Br
2], into the proof. Anyone have any idea??