[evolution619]

How do I determine the empirical formula in a hydrate?

Mass of empty crucible and lid 23.37g
Mass of crucible, lid and hydrate 24.13g
Mass of hydrate 0.76g
Mass of crucible, lid and anhydrous salt (first heating) 23.87g
Mass of crucible, lid and anhydrous salt (second heating) 233.18g
Mass of anhydrous salt 0.5g
Mass of water given off 0.26g
Mass of one molecule of anhydrous salt (from your instructor) 159.611g/mol

the answer should be in AB X xH2O so i need to find x
which is related to my other question on calculating the moles of water per mole of the anhydrous salt
so if I found the moles of water per anhydrous salt will I get x?

[Dan]

so if I found the moles of water per anhydrous salt will I get x?

yes

[JGK]

How do I determine the empirical formula in a hydrate?

Mass of empty crucible and lid 23.37g
Mass of crucible, lid and hydrate 24.13g
Mass of hydrate 0.76g
Mass of crucible, lid and anhydrous salt (first heating) 23.87g
Mass of crucible, lid and anhydrous salt (second heating) 233.18g
Mass of anhydrous salt 0.5g
Mass of water given off 0.26g
Mass of one molecule of anhydrous salt (from your instructor) 159.611g/mol

the answer should be in AB X xH2O so i need to find x
which is related to my other question on calculating the moles of water per mole of the anhydrous salt
so if I found the moles of water per anhydrous salt will I get x?

I'm assuming that should be 23.18 g