Agreed. If you want to get realy technical, you can think of this addition as the creation of an electrochemical cell:
One reaction was Al
(s) --> Al
3+(aq) + 3 e
-And the other is Cu
2+(aq) + 2 e- --> Cu
(s)And here's the deal. If you write each as a reduction:
Al
3+(aq) + 3 e
- --> Al
(s) E = E°Al
Cu
2+(aq) + 2 e- --> Cu
(s) E = E°Cu
Whenever you have two 'half reactions' like this, the one which has the lowest E° is more likely to occur as shown. In your case, E°
Cu would be lowest - hence the copper precipitate and the aluminum 'dissolves'.
All you need to do then is find a reaction like these, what occurs for a smaller number. THAT will make the aluminum precipitate from the solution for the exact same reason as the copper did.
Good luck!