okay, I think I've gotten it. Because equal amounts were added, I should of picked a number to figure out how many mL it would take to reach equilibrium.
The question doesn't state if the acid or the base is being titrated... so I am going to guess I'm going strong base into a strong acid. So I would need to figure out how many mL of HBr to reach equil.
If it were to be 100 mL:
(100mL)(.01)=(.005)(Ve)
1 mL = .005Ve
Ve=200 mL
So you would need 200 mL of .005 M HBr to titrate 100 mL of .01 M KOH. Because we only have 100 mL, we would be left would a more basic solution.