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Topic: Spectroscopy question  (Read 6303 times)

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Offline odicon

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Spectroscopy question
« on: March 18, 2010, 05:54:57 PM »
Indicate those of the following statements that are correct for the compound 13CH3OH

a. The carbon-13 spectrum will be a 1:2:1 triplet.
b. The proton NMR spectrum will be a 1:1 doublet and a broad singlet.
c. The broad singlet in the proton spectrum is due to the exchange of protons among methanol molecules.
d. Because of the oxygen, the IR spectrum will have a strong band around 1750 cm-1.
e. This compound will absorb in the visible region, and will therefore be coloured.
f. The mass spectrum should have a peak at mass 15.

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Hello,

this is what I came up with.
do you think my reasoning is right?

a -- is this false? it will be quartet right? because the C is attached to three H's.
b -- wouldnt this be quartet (from the H's on the methyl) and a broad singlet (from the H in OH)? is it false?
c -- i have a feeling that this is true but i am not sure  why
d -- false
e -- false
f -- true? because the methyl group (13CH3) can come off and lose a proton, making its mass 15. Or am I totaly wrong?

Thanks a lot.

Offline MOTOBALL

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Re: Spectroscopy question
« Reply #1 on: March 24, 2010, 07:45:14 PM »
f)  13CH3+. has m/z 16; will NOT lose H. to give m/z 15

Offline odicon

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Re: Spectroscopy question
« Reply #2 on: March 25, 2010, 04:02:54 AM »
Oh I see. Thanks for your reply!

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