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Topic: Dehydrating hydrates  (Read 7513 times)

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Offline roncarlston

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Dehydrating hydrates
« on: March 22, 2010, 10:55:45 PM »
I need to write three balanced equations to indicate what happens when these hydrates are dehydrated by mild heating.
                                                /\
for the first one  CuSO4 . 5H2O -------->  CuSO4 + 5H2O


did i do that correctly?

others that i have to write and balance

CoCl2 . 6H2O

MgSO4 . 10H2O

Offline nj_bartel

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Re: Dehydrating hydrates
« Reply #1 on: March 22, 2010, 11:51:36 PM »
yes

Offline MOTOBALL

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Re: Dehydrating hydrates
« Reply #2 on: March 23, 2010, 07:55:03 PM »
According to my textbook, the anhydrous salt (CuSO4) is formed only by heating
to 250 C----this is not mild !!

Heating to 100 C gives the monohydrate (CuSO4.H2O)--is this "mild" ??? maybe.

I suspect that CuSO4.5H2O may be unaffected  by really mild heating (30-50 C).

CoCl2.6H2O---look it up to learn about the inorganic chemistry of these salts

MgSO4.10H2O--look up the stable hydrate of MgSO4

Offline Schrödinger

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Re: Dehydrating hydrates
« Reply #3 on: March 24, 2010, 03:13:59 AM »
This is more of a coordination chemistry question. At 100 degrees (considered mild), the 4 H2O ligands are kicked out. But you need a higher temperature to break the hydrogen bonding that exists between the SO42- and H2O outside the coordination sphere

That should give you some clue to work on CoCl2.6H2O as well.
MgSO4.2H2O is the stable hydrate, I guess.

Or that's what I know. Please correct me if I am wrong.
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