This will be not complete - that is, just because I have not commented on something doesn't mean it was correct.
Substance: calcium chloride
Molecular equation and type when added to NaOH: N/A
It may depend on concentrations, Ca(OH)
2 is relatively weakly soluble.
Substance: zin powder
Molecular equation and type when added to HCl: Zn(s) + 2HCl (aq) ZnCl2 (aq) + H2 (g) ; O/R
Molecular equation and type when added to NaOH: Zn(aq) + 2OH(aq) Zn(OH)2 (s) ; PPTN
If I understand correctly, you have added zinc powder to two separate samples of acid and base? If so, why it is Zn(s) in teh first reaction and Zn(aq) in the second? Also - what is OH(aq)?
When added to water complete Ionic Equation: NH4+(s) + Cl-(s) + H2O(l) NH4+(aq) + Cl-(aq) + H2O(l)
NH
4Cl(s), it splits to ions when dissociating.
Substance: iron powder
Molecular equation and type when added to NaOH: Fe(s) + 2NaOH(aq) Fe(OH)2 (s) + 2Na(aq) ; PPTN
Are you sure iron hydroxide was produced? No such thing as Na(aq).
Substance: calcium oxide
When added to water complete Ionic Equation: Ca2+(aq) + O2-(aq) + 2H+ + O2-(aq) Ca(OH)2 (s)
No such thing as O
2-(aq), you start with CaO(s). Why 2H
+ + O
2-(aq) and not just H
2O?
Substance: sucrose
When added to water complete Ionic Equation: (this one has stumped me, any help is sought)
Just none, this is not an ionic substance.
Note: (l), (aq), (s), (g) - are not subscripts.