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Topic: Le Chatelier's Principle  (Read 20618 times)

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clewi00i

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Le Chatelier's Principle
« on: July 21, 2005, 10:24:58 AM »
I am trying to figure out the direction of shift in equilibrium when adding H2SO4 to the equation 2CrO4 + 2H = Cr2O7 + H2O.  After that, the shift by adding NaOH.  I understand why the shift occurs and what happens when it does, but am confused as to the direction of shift.  
« Last Edit: July 21, 2005, 10:31:28 AM by clewi00i »

Offline Yggdrasil

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Re:Le Chatelier's Principle
« Reply #1 on: July 21, 2005, 05:13:22 PM »
H2SO4 is an acid, so it will add H+ to the solution.  NaOH is a base, so it will remove H+ from the solution.  This should point you toward the answer.

GCT

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Re:Le Chatelier's Principle
« Reply #2 on: July 22, 2005, 12:15:21 AM »
you got to think of it in terms of the relative rate constants.

Offline sdekivit

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Re:Le Chatelier's Principle
« Reply #3 on: July 26, 2005, 04:28:13 AM »
I am trying to figure out the direction of shift in equilibrium when adding H2SO4 to the equation 2CrO4 + 2H = Cr2O7 + H2O.  After that, the shift by adding NaOH.  I understand why the shift occurs and what happens when it does, but am confused as to the direction of shift.  

you must remember that the adaption will be such that equilibrium maintains --> K doesn't change.

so if we add H2SO4 and thus H+ we have more H+ on the left. There are more effective collisions between chromate and H+ resulting in the equilibrium shift to the right.

Another method:

K = [Cr2O7(2-)] / [CrO4(-)][H+]^2

when we add H+ the denominator of K rises, resulting in a lowering of the equilibriumconstant. The equilibrium will shift to that side such that the change will be undone and there is no effect on the system. To accomplish this, the numerator must rise and thus the equilibrium will shift to the right (the side of the numerator)--> [dichromate ion] rises.

When we add a base, we capture H(+) away from the system, resulting in less effective collisions between chromate and H+, resulting in the equilibrium shifting to the left.

Or: [H+] decreases, resulting in a rise of the equilibriumconstant. Therefore the numerator must decrease, so the equilibrium will shift to the left.

Offline Donaldson Tan

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Re:Le Chatelier's Principle
« Reply #4 on: July 28, 2005, 03:33:45 PM »
Le Chatlier's Principle (LCP) states that a chemical system at equilibrium will counter the stress acting on it.

eg. A + B <-> C + D (dH < 0)

adding A to the system means the reaction removing A is favoured. in another words, the forward reaction is favoured.

adding D to the system means the reaction removing D is favoured. in another words, the backward reaction is favoured.

heating the system means the reaction removing heat is favoured. this means the endothermic reaction is favoured. in another words, the backward reaction is favoured.

i hope this makes LCP easier to understand.
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Offline sdekivit

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Re:Le Chatelier's Principle
« Reply #5 on: July 28, 2005, 03:45:26 PM »
heating the system will let all reaction go faster, since rising the temperature will let the molecules move faster and thus more effective collisions. But the endothermic reaction in particular will run 'more faster then faster'.

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