Okay, so the question says "Calculate the value of Ksp for AgCL(s) at 10 degrees C."
I calculated the solubility for AgCl in the problem above, and it's 4.13x10^-6 M; equation is AgCl(s) <--> Ag+(aq) + Cl-(aq).
I asked my teacher and she said not to ICE, just to use the Ksp equation, but that doesn't involve the reactants, so how exactly am I supposed to find the solubilities for Ag+ and Cl- to plug into the equation?
thanks