so you have 118 mL of 100%. if you double the volume, you'd get 50% concentration, right? which would involve 118 mL of filler. as such, to turn 100% into 5%, your dilution needs to be in a ratio of 1:20. so if 118 mL is that 1 part, the other 19 parts of equal volume will be filler. that means 19*118 = 2242 mL.
on the other hand, if you don't want to use all of it, you can think of it another way. take 1 mL of concentrate and 19 mL of dilute, this will give you 20 mL of 5%. you can scale this up for as much or as little as you'll need.
you don't need moles or molar mass. you would need the chemical composition of the cleaning agent to get moles.