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Topic: pH calculation of a monoprotic acid  (Read 3991 times)

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Offline jtruong

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pH calculation of a monoprotic acid
« on: April 29, 2010, 03:16:30 AM »
I am trying to work out the pH of 12.0 M HNO3.

This is what I did:
Since HNO3 is a strong acid, it ionises completely. This means that [H3O+] is 12 mol L-1.

pH=-log[H30+]
pH=-log[12]
pH= -1.08

The answers say that pH is 1.08. I am pretty sure pH is always greater than zero (not 100% though). This means that my answer is wrong. What am I doing wrong?

Offline AWK

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Re: pH calculation of a monoprotic acid
« Reply #1 on: April 29, 2010, 05:02:38 AM »
Calcualtions of pH for such a big concentration of strong acid are meaningful. You should use the activity coefficients.
Concerning the question about negative pH - this is possble!
AWK

Offline jtruong

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Re: pH calculation of a monoprotic acid
« Reply #2 on: April 29, 2010, 07:21:52 AM »
Thanks for replying.

Never heard of activity coefficients. Could you please expand on that. I am guessing this is not in my course though.

By the way, do my calculations look ok?

Offline Borek

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Re: pH calculation of a monoprotic acid
« Reply #3 on: April 29, 2010, 09:58:30 AM »
http://www.chembuddy.com/?left=pH-calculation&right=ionic-strength-activity-coefficients

Your approach is more or less correct, although nitric acid is the weakest of the strong ones, so at such high concentration you should not only take activities into account, but also fact that it will be not 100% dissociated.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline jtruong

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Re: pH calculation of a monoprotic acid
« Reply #4 on: April 30, 2010, 07:34:02 AM »
Thanks for the clarification. I have asked my chem teacher and he said that it was a error in the answers.


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