November 15, 2024, 04:55:49 AM
Forum Rules: Read This Before Posting


Topic: oxidation of organics in water using AOP  (Read 2148 times)

0 Members and 1 Guest are viewing this topic.

Offline Civilwaters

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
oxidation of organics in water using AOP
« on: May 11, 2010, 06:16:27 AM »
I am doing a project on water treatment and the oxidation of organics in water using AOP (i.e. the hydroxyl radicals)
and I need someone (hopeful a few) to check this and tell me if its right.


[what happens in the ROOH +R*=>=>CO2+H20]

1.       R + OH* => R* +H2O
2.       R* +O2 => ROO*
3.       ROO* + RH => ROOH + R*
4.       ROOH => CO2 + H2O
 Using R = CH3-CH3
 R* = CH3-CH2*
ROO* = CH3-CH2-O-O*
ROOH = CH3 -CH2-O-OH

Therefore ROOH => CO2 & H2O

is CH3-C(H2)-O-OH + O2 => CH3* + CO2 + H2O + OH*
(So the CH3* + 2x O2 => CO2 + H2O + OH*)

So in effect R is now one C less with the carbon chain being continually reduced, as at the end of each cycle a OH* is available to repeat the process.   

This is a chain reaction as long as enough O2 is present to sustain the reaction.

Sponsored Links