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Topic: energy changes!  (Read 2494 times)

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Offline mescalito89

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energy changes!
« on: May 18, 2010, 03:17:36 PM »
How would i solve this problem

Calculate the DeltaH for the following reaction

C6H6 + 3/2 O ----> 6C + 3H20

thank you

Offline S.V.

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Re: energy changes!
« Reply #1 on: May 19, 2010, 12:40:44 AM »
The formula for DeltaH is DeltaHrxn = summation [nDeltaHf(products) - mDeltaHf(reactants)].
Note that DeltaH for products and reactants is taken to be at standard conditions.
m and n are numbers of moles.
Therefore, you will have DeltaHrxn=6(DeltaH C) + 3(DeltaH H2O) - 1(DeltaH C6H6) - 1.5(DeltaH O).
You can look up the standard enthalpies of the elements and compounds in a chemistry book.

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