[sillybilly]

hello im a new here and im stuck on a chemistry question can u plz help me?

The question is:
The volume of solution in 50ml, 0.242 mol L^-1 hydrochloric acid was diluted to the volume in 500ml. Calculate molarity of the diluted solution.  

also can u explain how to USE C₁V₁ = C₂V₂

thank you  

[Borek]

http://www.chembuddy.com/?left=concentration&right=dilution-mixing

How to use? Basic algebra skills - solve for the unknown.

[sillybilly]

after u sub that (remembering to change ml to L) into equation and solving it
it doesnt seem like the right answer

my working out:
V₁ = 50ml = 0.5L

C₁ = 0.242 mol L^-1

V₂ = 500ml = 5L

using the formula your sun these into it and re-arrange...

and then u get 0.00242.... (dat doesnt sound right...)

so if i got that right how do u work out molarity?

[Borek]

V₁ = 50ml = 0.5L

No. How many milliliters in 1L?

V₂ = 500ml = 5L

No. See above.

using the formula your sun these into it and re-arrange...

and then u get 0.00242.... (dat doesnt sound right...)

Show details of what and how you did. And please use English. No idea what you want me to do with my sun.

[sillybilly]

ohhh its supposed to be sub  haha and its english 

okay so its:

V₁ = 50ml = 0.05    C₁ = 0.0242     V₂ =500ml = 0.5

therefore once its into the equation it looks like this

0.0242 x 0.05 = C₂ x 0.5

0.0242 x 0.05 = C₂
-------------
 0.5


C₂ = 0.00242 

i obviously dont get it..

[Borek]

Your approach is correct, but you should pay more attention - is the initial concentration 0.242M or 0.0242M?

And why do you think 0.00242M is wrong?

[sillybilly]

ohh my life im so wrong its actually 0.242.... sorry
but the answer to that question is right... thank you then

[sillybilly]

ohhh its supposed to be sub  haha and its english 

okay so its:

V₁ = 50ml = 0.05    C₁ = 0.242     V₂ =500ml = 0.5

therefore once its into the equation it looks like this

0.0242 x 0.05 = C₂ x 0.5

0.0242 x 0.05 = C₂
-------------
 0.5


C₂ = 0.00242 

i obviously dont get it..