Any Hints as to how to approach this calculation
Calculate the kcat of Enzyme 2, given the following data.
Vmax = 40,000 μmoles/sec, in an assay mixture of 1 mL
Amount of enzyme used in one assay (1 mL) = 5 μL of a 1 mg/mL solution of enzyme
MW of the enzyme = 50,000 gm/mol
Km of the substrate = 3 mM
My Approach
Kcat= Vmax/Et
I know my Vmax but I dont know how to find Et