I have a problem here I was hoping to get a little help with. Here is the question:
What mass of Al(OH)3 can be obtained by reacting 25.0g Al4(OH)3 with water?
In the solution in my textbook it shows the balanced equation as:
Al4C3 + 12H20 --> 3CH4 + 4Al(OH)3
Now... I know how to balance the equation, and I understand the reactants on the left hand side, but I'm a little confused as to how they are getting the methane in the product. Can somebody help me to understand? Thanks!