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Topic: oxidation  (Read 3266 times)

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Offline Ankesh

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oxidation
« on: July 03, 2010, 02:50:35 AM »
is it true that when di keto compounds are formed as products after oxidation with hot KMnO4 they break up further????even when we r nt using HIO4

Offline Jorriss

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Re: oxidation
« Reply #1 on: July 03, 2010, 03:42:55 AM »
I don't know what a diketo is.

That being said, Aldehydes are further oxidized to carboxylic acids generally.

And ketones are not further reduced as there is no available hydrogen to use.

Offline Ankesh

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Re: oxidation
« Reply #2 on: July 03, 2010, 03:49:44 AM »
compounds like (CH3-CO-CO-COOH) are diketo compounds..(di ketones)
i know aldehydes are further oxidised to carboxylic acid if hydrogen is present(everyone knows that)..what i am asking is why do the diketo compounds break up further even when not using HIO4

Offline AnkurGel

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Re: oxidation
« Reply #3 on: July 03, 2010, 10:39:24 AM »
An alkyne (R-CC-R|) when treated with KMnO4 in neutral medium gives diketone (R-CO - CO-R|.
even if some heat is provided or acquired, it will consequently break to form carboxyilic acids to give (RCOOH and R|COOH). So yeah, it's true that a diketone compound formed after oxidation and breaks further in hot KMnO4.
It's a strange thing, but when you are dreading something, and would give anything to slow down time, it has a disobliging habit of speeding up.

Offline Jorriss

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Re: oxidation
« Reply #4 on: July 03, 2010, 01:17:13 PM »
ooo, that's cool. Thanks :P

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