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Topic: DIlutions and such  (Read 2437 times)

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Offline luysion

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DIlutions and such
« on: August 15, 2010, 12:59:31 AM »
hey,got this Q in my textbook with no answer, i really want to work through it but i dont know whether or not the A i get is right or wrong..

A 24 hour urine sample is collected and analysed for albumin using the BCG assay. The total volume of urine is 0.8L

0.9 mL of a 1 in 2 dilution is analysed spectrophotometrically and the absorbance is 0.2. This value is in the linear part of a standrd curve generated for this assay. From the standard curve the absorbance of 0.1mg of albumin is 0.1 and 0.5 mg of albumin is 0.5.

Using a molecular weight for albumin of 66000, how many μmol of albumin are present in the original urine sample. (only enter the number and use no more than 2 decimal places)

its a little complex for me :(
appreciate the help yea

Offline Borek

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Re: DIlutions and such
« Reply #1 on: August 15, 2010, 04:02:36 AM »
Do it step by step.

What is concentration of albumin in diluted sample?

In undiluted sample?

What is mass of albumin in the original sample?

How many moles is it?
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