I've had a go at the question but I'm unsure if its correct, I'm a little confused as to when the charge is to be 0 or 1/2.
Here is the question:
Oxytocin is a nonapeptide (a nine-residue peptide) hormone involved in the milk-releasing response in lactating mammals. the sequence of a synthetic version of oxytocin is shown bellow:
Cys-Phe-Ile-Glu-Asn-Cys-Pro-His-Gly
what is the net charge of this peptide at (a) pH 2.3, (b) pH 6.0, (c) pH 8.5 and (d) 11.5 ?Assume that the ionisable groups have the following pKa values: Glu 4.2, His 6.0, N-term-NH
3+, C-term -COOH 2.3. The disulfide bond is stable between pH 2.3 and 12.5.
This is how i worked it out, but as i said I'm a little confused about the 1/2 and 0 values for the charge. I worked off pH>pKa proton tends to be off, pH<pKa the proton tends to be on and pH=pKa half of the molecules are protonated and half are deprotonated.
NH3+ Glu His COOH
pKa 10.3 4.2 6.0 2.3
(a) pH 2.3net charge +1 +1 +1 +1/2
Net charge = +3.5
(b) pH 6.0net charge +1 -1 +1/2 -1
Net charge = -0.5
(c) pH 8.5net charge +1 -1 -1 -1
Net charge = -2
(d) pH 11.5net charge 0 -1 -1 -1
Net charge = -3
It would be greatly appreciated if someone could let me know if i did it right and if not explain where i went wrong. Thanks