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Topic: Optically Active/InActive Question  (Read 3753 times)

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Offline MetsFan09

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Optically Active/InActive Question
« on: September 12, 2010, 08:17:31 PM »
The answer to the question is C but can someone explain to me why it is?  Thanks a bunch.



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Offline Jorriss

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Re: Optically Active/InActive Question
« Reply #1 on: September 12, 2010, 09:03:18 PM »
Have you drawn all possible products of hydrogenating each of those compounds?
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Offline MetsFan09

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Re: Optically Active/InActive Question
« Reply #2 on: September 12, 2010, 09:33:03 PM »
Wouldn't they just lead to the double bond on each going away?  I know choice A is achiral so it can't produce anything optically active.  But what about the others?
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Offline dunno260

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Re: Optically Active/InActive Question
« Reply #3 on: September 12, 2010, 10:50:16 PM »
You have to remember the mechanism of hydrogenation.  Though it does add across a double bond to reduce the alkene to an alkane, it does so in a very specific manner.
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