[Kalibasa]

I have never seen normality before, so I'm really having trouble understanding it. Here is the problem:

"If 1.0 mL of 10.0 N NaOH is added to a liter of the buffer prepared in (a), how much will the pH change?" The buffer from part a was a phosphate buffer of 0.058 M HPO4^2- and 0.042 M H2PO4^-.

I got the problem right after the answer told me that 1.0 mL of 10.0 N NaOH was 0.010 mol, but I have no idea how they got this. I looked up normality online and know the basic definition(gram equivalents/liters solution), and that it is specific for particular reactions. But I don't even know how to set up a basic equation to find the molarity here. Am I supposed to first solve for gram equivalents? Because I thought that the gram equivalent should be 40 g, the molecular weight of NaOH, because you only would get one equivalent of OH- when it dissociates...?

Basically I'm totally lost.

[Borek]

If gram equivalent is mass, equivalent could be called "mole equivalent", as it refers to number of moles. Thus you don't have to go through mass, you can easily calculate number of equivalents per mole.