#1) How many milliliters of 0.55 M HCl are needed to react with 5.9 g of CaCO3?
2 HCl(aq) + CaCO3(s) ---> CaCl2(aq) + CO2(g) + H2O(l)
#2How many grams of solid barium sulfate form when 14.2 mL of 0.160 M barium chloride reacts with 64.4 mL of 0.055 M sodium sulfate? Aqueous sodium chloride is the other product.