Greetings folks. Been a while since I've created a thread...and now I have a bothersome mechanism question which has prompted me to do so!
I discussed this with my friend to no avail : The compound Ph2C=CHBr when reacted with KNH2 yields? The answer is Ph-C≡C-Ph.
We figured it would go through either of two mechanisms -
1. The potassium variant of sodamide given here is a strong base. So it abstracts the proton present on the carbon having Br. This forms a carbanion. Now a migration occurs, and the Ph anti in conformation to the anion migrates, somehow causing the formation of the triple bond.
2. An alpha elimination occurs, and both -H and -Br are lost, leading to the formation of a carbene. The -Ph group previously cis in conformation to the bromine atom migrates to fulfill the carbene's need for electrons. Now Ph-C+=C--Ph becomes the product given above.
Which mechanism is correct? And why?