[oCh3m_nub]

How do I draw structures and give the IUPAC name of the constitutional isomers the aldehydes with molecular formula C₆H₁₂O.

Would the structures look like this:

1. C=C-C-C-C-C-OH =hexanolaldehydes?

2. C=C-C-C-C-C =hexanol-2-aldehydes?
                  l
                 OH

3. C=C-C-C-C-C = hexanol-3-aldehydes?
               l
              OH

4. C=C-C-C-C-C
            l
           OH

5. C=C-C-C-C-C
         l
        OH

6. C=C-C-C-C-C
     l
    OH                  

 
           CH₃
            l
7. H₃C-CH-CH-CHO
                      l
                      CH₃

[sjb]

Only structures like 7 are still aldehydes, are you sure that's all you need, as opposed to unsaturated alcohols, ethers etc?

[oCh3m_nub]

so theres only one option and way to write out this formula is #7?

[sjb]

so theres only one option and way to write out this formula is #7?

Well, if you're asked to draw out all the aldehydes with formula C₆H₁₂O, and you draw things that aren't aldehydes, then that seems wrong to me. There are other aldehydes you can draw, though. 7 is not the only extra one.