January 15, 2025, 12:12:58 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Change In Enthalpy, Another Quick Question  (Read 2115 times)

0 Members and 1 Guest are viewing this topic.

Offline Boxxxed

  • Full Member
  • ****
  • Posts: 203
  • Mole Snacks: +1/-0
Change In Enthalpy, Another Quick Question
« on: October 16, 2010, 05:27:00 PM »
We have

C + 2H2 + 1/2 O2 ----> CH3OH

The heat of formation value is -201.0 KJ/mol

We want to find the change in enthalpy is 2.4 g of carbon is used

Moles Carbon = 0.1998

0.1998x(-201.0) = -40.2 KJ

Why is the book dividing 201.0 by 0.1998 to get -1006.0 KJ/Mol C?

We are using less carbon so there should be less energy released.

Logged

Offline JustinCh3m

  • Regular Member
  • ***
  • Posts: 95
  • Mole Snacks: +12/-8
    • CollegeChemistryNotes
Re: Change In Enthalpy, Another Quick Question
« Reply #1 on: October 18, 2010, 11:46:18 PM »
what you've done is correct.  Are you using Zumdahl by any chance?  I've found quite a few errors in the Zumdahl text.
Logged

Offline Boxxxed

  • Full Member
  • ****
  • Posts: 203
  • Mole Snacks: +1/-0
Re: Change In Enthalpy, Another Quick Question
« Reply #2 on: October 20, 2010, 09:52:33 AM »
It's a book of walkthroughs through different types of questions. Surviving University by Maria Sokolova
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links