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Enthalpy of Neutralization
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Topic: Enthalpy of Neutralization (Read 4016 times)
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Enthalpy of Neutralization
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on:
October 28, 2010, 05:20:48 PM »
In a lab I've mixed 50 ml of each 1.00M/L of NaOH and 50 ml of 1.10 M/L of HCl.
To find qreaction do I use the specific heat of water?
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Borek
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Re: Enthalpy of Neutralization
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Reply #1 on:
October 28, 2010, 05:27:42 PM »
Yes.
It would be better to use specific heat of NaCl solution of correct concentration, but difference is not that large.
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ChemBuddy
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Re: Enthalpy of Neutralization
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Reply #2 on:
October 28, 2010, 05:40:28 PM »
Also..
I've already calculated the calorimeter constant using hot and cold water and the excess energy that the calorimeter absorbed.
They gave us the formula Ccal = qcal / DT
Why is there no mass?
To calculate qcal for the acid-base reaction would I use qcal = Ccal (from previous experiment) / DT?
I'm lost as to where the mass component went.
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Re: Enthalpy of Neutralization
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Reply #3 on:
October 29, 2010, 03:26:09 AM »
Mass is necessary when dealing with specific heats, heat capacity already takes mass into account.
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ChemBuddy
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Re: Enthalpy of Neutralization
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Reply #4 on:
October 29, 2010, 01:22:24 PM »
Last related question
When they are asking for qwater am I calculating mass from moles of reactants and subtracting it from the final mass of the mixture to find mass of water then using q=mcDT? I find it odd that they aren't asking for q of the whole solution instead.
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Re: Enthalpy of Neutralization
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Reply #5 on:
October 29, 2010, 02:49:03 PM »
We are asked to calculate qwater, qcal and qrxn for this acid-base reaction.
qrxn is heat produced by 0.0501 mol NaOH reacting with equal number of moles of HCl.
qcal is heat absorbed by calorimeter
What exactly is qwater?
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