[LHM]

The decomposition of NO

2 NO(g) N₂(g) + O₂(g)

follows simple second order kinetics. In a particular experiment, it takes 2000 seconds for the concentration of NO to fall from 2.80*10^-3 M. If a second experiment is performed with the initial concentration of NO at 0.0820 M, calculate how long it will take for the concentration to fall to 4.10*10^-2 M.

A) 1.71*10² sec
B) 1.00*10³ sec
C) 2.86*10³ sec
D) 4.12*10³ sec

How do you do this if you don't know what the concentration of the original experiment fell to after the 2000 seconds?

[Schrödinger]

Yeah.. The question, I believe, is incomplete.

How do you do this if you don't know what the concentration of the original experiment fell to after the 2000 seconds?

Well, you cannot