Hello, the question I am given is:
Determine the pH of the solution that is created by mixing 45.2 mL of 2.51×10-3 M HI with 154 mL of 9.32×10-4 M MgH2.
I'm pretty sure I have to make a net ionic equation, however I'm a bit confused about how to do that with these two chemicals and also how the coefficients work when calculating.
2HI + MgH2 + 4H2O = MgI2 + 4 H3O
This equation makes the most sense to me, although it doesn't seem right.