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Topic: Reducing a Formula (Read 3825 times)
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XxslbabesxX
Regular Member
Posts: 22
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Junior Student
Reducing a Formula
«
on:
September 02, 2005, 10:18:32 PM »
This may be a silly question, but I was wondering why, for example, Cr
2
O
6
has to be reduce to CrO
3
(according to my teacher), but for something like Octane, C
8
H
18
, it does not reduce to C
4
H
9
.
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Yggdrasil
Retired Staff
Sr. Member
Posts: 3215
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Gender:
Physical Biochemist
Re:Reducing a Formula
«
Reply #1 on:
September 03, 2005, 12:43:27 AM »
It has to do with whether the compound is ionic or covalent. In ionic compounds, the formula represents the ratio of atoms in the crystaline solid. There are no actual molecules of CrO
3
. Therefore, the empirical forumla is used. However, in a covalently-bound compound, actual molecules do exist and these molecules consist of the exact number of atoms described in the molecular structure.
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XxslbabesxX
Regular Member
Posts: 22
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Gender:
Junior Student
Re:Reducing a Formula
«
Reply #2 on:
September 03, 2005, 11:10:12 PM »
Thank you for your help
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Reducing a Formula